(I am taking assumption to explain the method, this method works well with any binary representation of the number)
Assumption: Let's say the 8-bit number is 10011110.
Method-
1 0 0 1 1 1 1 0
1 1 1 1 1 1 1 1 Apply XOR of the 2 numbers
--------------
0 1 1 0 0 0 01
So, we are able to find a 1's complement of the number 10011110 with a single XOR function as shown in this simple example.
This method works for any binary number representation.
Suppose you have an 8-bit binary number and you want to check whether the number is non-zero or not:
(I am taking assumption to explain the method, this method works well with any binary representation of the number)
Assumption: Let's say the 8-bit number is 10011110.
Method-
1 0 0 1 1 1 1 0
1 1 1 1 1 1 1 1 Apply AND of the 2 numbers
--------------
1 0 0 1 1 1 1 0
So, we are able to find a number 10011110, from which we can say that the number is non-zero, with a single AND function as shown in this simple example.
This method works for any binary number representation.
However, this method is useful to check for a single bit whether it is zero or not.
As an example:
We will check for the input 10011110, whether the bit at position 3 is '0' or not. (considering the Least significant bit as 1st bit)
10 0 1 1 1 1 0
000 00 1 0 0 Apply AND of the 2 numbers
--------------
000 00 1 0 0
Here, the result is >0. Therefore,
we can say that for a number 10011110, the bit at position 3 (
10011110) is 1.
In general, to check the nth bit for the number, keep the nth bit as 1 and reset the rest of the bits in the input number, with which you are going to perform AND operation.
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